Census tract · Broward County

Census Tract 1008.04, Broward County, Florida

Census Tract 1008.04, GEOID 12011100804, in Broward County, Florida, mostly within Pembroke Park (59% of its census blocks). 4,208 residents in the ACS 2020-2024 5-year estimates (±341); the 2020 Census counted 4,524.

Residents, 2020-2024

4,208

±341 (90% margin)
2020 Census count: 4,524

Median household income

$53,558

±$6,780 (90% margin)
Broward County: $77,633

Median home value

$286,600

±$169,615 (90% margin)
Broward County: $414,600

Median gross rent

$1,557

±$154 (90% margin)
Broward County: $1,907

Where is Census Tract 1008.04?

Census Tract 1008.04 is one of 417 census tracts in Broward County, Florida. It covers 0.34 square miles of land, 13,151 residents per square mile in 2020. Its GEOID, 12011100804, names it uniquely (how tract numbers and GEOIDs work).

Places Census Tract 1008.04 lies in (share of its 2020 census blocks)
PlaceShare of the tract
Pembroke Park59%
West Park41%
Census Tract 1008.04 (marked with a dot) in Broward County, Florida. Boundaries: Census Bureau 2024.
100610071008.0398.0398.09 1008.04 0.5 mi
Census Tract 1008.04 (shaded) and the tracts that border it, numbered. Boundaries: Census Bureau 2024 cartographic boundary file, 1:500,000. Dashed: tracts outside Broward County.

5 census tracts border Census Tract 1008.04: Tract 1006 ($70,459), Tract 1007 ($47,227), Tract 1008.03 ($89,816), Tract 98.03 in Miami-Dade County ($80,568) and Tract 98.09 in Miami-Dade County ($72,727). The figure in brackets is each tract's median household income.

Whether a tract counts as low- or moderate-income for bank lending (the Community Reinvestment Act) is set by the FFIEC against its metro area's family income: look it up in the FFIEC census geocoder.

Source: 2024 Gazetteer and 2020 block assignment files, U.S. Census Bureau · Census reference files

How many people live in Census Tract 1008.04?

The 2020-2024 American Community Survey puts Census Tract 1008.04's population at 4,208 (±341) in 1,543 households; the 2020 Census counted 4,524 residents and 1,678 housing units.

Counts, ACS 2020-2024 5-year estimates
MeasureTract 1008.04Pembroke ParkBroward CountyFlorida
Total population4,208±3416,3601,977,12922,416,077
Households1,543±2012,477753,9568,752,810
Average household size2.60±0.362.492.602.51
Housing units1,653±1943,698866,01910,256,470

Source: American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026); 2020 Census P.L. 94-171 · Check it at data.census.gov

Who lives in Census Tract 1008.04?

The median resident of Census Tract 1008.04 is 31.9 years old; 33.6% are under 18 and 10.9% are 65 or older. The largest group is non-Hispanic Black residents at 64.2%, then Hispanic or Latino residents (of any race) at 28.7%. 41.9% of residents were born outside the United States.

Age, origin, education, ACS 2020-2024 5-year estimates. Race groups are non-Hispanic; Hispanic includes any race.
MeasureTract 1008.04Pembroke ParkBroward CountyFlorida
Median age31.9±6.439.441.342.6
Under 18 years33.6%±7.4 pts28.3%20.8%19.5%
65 years and over10.9%±4.2 pts18.7%17.9%21.3%
Hispanic or Latino (any race)28.7%±11.1 pts35.7%32.8%27.4%
White alone, not Hispanic5.9%±3.5 pts18.0%30.7%50.4%
Black or African American alone, not Hispanic64.2%±11.6 pts44.4%27.4%14.6%
Asian alone, not Hispanic0.0%±1.2 pts0.7%3.6%2.9%
American Indian and Alaska Native alone, not Hispanic0.0%±1.2 pts0.0%0.1%0.1%
Native Hawaiian and Other Pacific Islander alone, not Hispanic0.0%±1.2 pts0.0%0.1%0.1%
Two or more races, not Hispanic1.3%±2.3 pts1.1%4.3%3.8%
Some other race alone, not Hispanic0.0%±1.2 pts0.0%1.1%0.7%
Born outside the United States41.9%±12.0 pts51.7%36.9%21.9%
Speak a language other than English at home (age 5+)54.7%±12.7 pts64.7%43.8%30.6%
Civilian veterans (age 18+)1.8%±1.9 pts2.5%3.9%7.4%
With a disability11.8%±4.2 pts11.5%11.3%13.7%
No health insurance coverage10.2%±5.8 pts12.1%12.5%11.5%
High school graduate or higher (age 25+)85.9%±6.9 pts80.9%90.4%89.9%
Bachelor's degree or higher (age 25+)16.2%±8.3 pts17.6%36.7%34.1%
Graduate or professional degree (age 25+)11.2%±6.9 pts10.2%14.3%12.9%
Lived in the same house a year earlier87.2%±7.8 pts84.9%87.1%86.3%

Source: American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026) (Data Profiles DP02, DP05) · Check it at data.census.gov

What do households in Census Tract 1008.04 earn?

Half of the 1,543 households in Census Tract 1008.04 earn less than $53,558 a year (±$6,780), against $77,633 across Broward County: 338th highest of the county's 411 tracts with a reliable estimate. 25.3% of residents live below the poverty line.

Income and poverty in 2024 dollars, ACS 2020-2024 5-year estimates
MeasureTract 1008.04Pembroke ParkBroward CountyFlorida
Median household income$53,558±$6,780$52,928$77,633$74,568
Mean household income$62,036±$10,764$62,599$109,281$105,967
Per capita income$23,601±$5,338$25,014$43,052$42,609
People below the poverty line25.3%±14.1 pts26.8%12.2%12.6%
Children under 18 below the poverty line29.3%±23.3 pts32.6%15.7%16.5%
Households receiving SNAP26.6%±11.1 pts23.2%13.2%12.6%
Households with a computer94.0%±5.5 pts95.0%96.9%96.6%
Households with a broadband subscription87.7%±8.5 pts88.9%92.1%91.6%

Source: American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026) (Data Profile DP03) · Check it at data.census.gov

What does housing cost in Census Tract 1008.04?

Owners occupy 13.8% of Census Tract 1008.04's occupied homes and renters 86.2%. The median owner-occupied home is valued at $286,600 by its owner (±$169,615). The median renter pays $1,557 a month including utilities, and 49.7% of renters pay 35% or more of their income on rent.

Housing, ACS 2020-2024 5-year estimates
MeasureTract 1008.04Pembroke ParkBroward CountyFlorida
Median home value (owner-occupied)$286,600±$169,615$105,300$414,600$359,000
Median gross rent$1,557±$154$1,556$1,907$1,669
Renters paying 35% or more of income on rent49.7%±13.3 pts48.1%55.4%50.2%
Median monthly owner costs, with a mortgage$1,552±$772$1,602$2,433$1,959
Owner-occupied homes13.8%±7.8 pts32.0%63.6%67.6%
Renter-occupied homes86.2%±7.8 pts68.0%36.4%32.4%
Housing units1,653±1943,698866,01910,256,470
Single-family detached homes9.3%±6.1 pts4.0%40.0%54.7%
Mobile homes0.0%±3.1 pts53.4%2.6%8.0%
Built 2020 or later0.0%±3.1 pts0.2%1.3%3.2%
Built 2010 to 20190.0%±3.1 pts2.6%5.7%11.0%
Built 1939 or earlier0.5%±1.1 pts0.2%0.7%1.9%
Households with no vehicle18.5%±8.5 pts14.3%6.8%6.0%

Source: American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026) (Data Profile DP04) · Check it at data.census.gov

How do people in Census Tract 1008.04 get to work?

77.0% of Census Tract 1008.04's workers drive alone. The average trip to work takes 34.9 minutes.

Work and commuting, ACS 2020-2024 5-year estimates
MeasureTract 1008.04Pembroke ParkBroward CountyFlorida
In the labor force (age 16+)65.6%±5.5 pts57.1%66.3%59.8%
Unemployment rate3.9%±3.1 pts3.9%5.4%4.8%
Drove alone to work77.0%±9.3 pts74.7%69.7%70.2%
Carpooled3.2%±4.0 pts8.4%9.8%9.2%
Public transportation9.0%±7.9 pts8.0%1.8%1.2%
Walked1.4%±1.8 pts1.3%1.2%1.4%
Worked from home6.2%±5.2 pts4.0%14.7%15.7%
Mean travel time to work34.9 min±9.632.5 min29.1 min28.0 min

Source: American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026) (Data Profile DP03) · Check it at data.census.gov

How does Census Tract 1008.04 compare with the other tracts in Broward County?

Among Broward County's tracts with a reliable estimate, Census Tract 1008.04 ranks as shown below (1 = highest).

Census Tract 1008.04's rank among the tracts of Broward County and of Pembroke Park
MeasureIn Broward CountyIn Pembroke Park
Population233rd of 4152nd of 3
Residents per square mile23rd of 4161st of 3
Median household income338th of 4111st of 3
Per capita income372nd of 4142nd of 3
Median home value318th of 4001st of 3
Median gross rent328th of 3902nd of 3
Poverty rate31st of 2782nd of 3
Bachelor's degree or higher376th of 4093rd of 3
Median age389th of 4153rd of 3
Owner-occupied share404th of 4123rd of 3

The tracts next to it on Broward County's income ladder

Median household income, ACS 2020-2024 5-year estimates
TractRankMedian household incomeResidents
Tract 903.01335th$53,750±$10,912 · within the margin of this tract2,343
Tract 202.13336th$53,747±$2,660 · within the margin of this tract3,709
Tract 601.07337th$53,716±$8,410 · within the margin of this tract5,019
Tract 1008.04338th$53,558±$6,7804,208
Tract 601.17339th$53,532±$9,896 · within the margin of this tract6,642
Tract 904.04340th$53,450±$29,328 · within the margin of this tract4,146
Tract 205.02341st$53,304±$15,352 · within the margin of this tract8,358

"Within the margin": the two incomes differ by less than their combined 90% margins, so the survey cannot say which is higher and the ranks between them are not firm.

Source: PlainCities ranks computed from the American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026) · How ranks are computed

How reliable are the figures for Census Tract 1008.04?

2 of the 18 figures for Census Tract 1008.04 on this page carry a coefficient of variation over 40% and are marked with a ring: they come from a small sample, so read them as rough.

A census tract's figures rest on a few hundred sampled households over five years, so its margins are wider than a city's. Two tracts differ only when the gap between them is larger than their combined 90% margin (the square root of the sum of the two squared margins). How to read a margin of error.

Source: American Community Survey 2020-2024 5-year estimates, U.S. Census Bureau (released January 2026): margins of error as published · Check it at data.census.gov

How these figures are made: methodology and release checks · reading a margin of error · every state · corrections